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Term 1 · Weeks 9–10 · Functions and Their Graphs

Standard problem

Standard

What is the minimum value of f(x)=(x−2)2−3f(x) = (x - 2)^2 - 3?

Show step-by-step solution

Answer: -3

  1. The function is in vertex form f(x)=a(x−h)2+kf(x) = a(x-h)^2 + k with vertex (2,−3)(2, -3).
  2. Since a=1>0a = 1 > 0 the parabola opens upward, so the minimum value is k=−3k = -3.

Common errors to watch for

  • Giving x=2x = 2 (where the minimum occurs) instead of the minimum value −3-3.

Budget of Work competencies

  • gm11.t1.w10.c1
    Sketch the graph of the following functions: linear, absolute value, quadratic, square root, or cube root with or without technology.

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