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Term 3 · Week 1 · Compound Interest

Challenge problem

Challenge

How much must be invested today at 6% compounded monthly to have ₱100,000 in 5 years?

Show step-by-step solution

Answer: 74137.22 ₱

  1. i=0.005i = 0.005, n=60n = 60.
  2. P=F(1+i)n=100,0001.00560≈100,0001.348850=74,137.22P = \dfrac{F}{(1+i)^n} = \dfrac{100{,}000}{1.005^{60}} \approx \dfrac{100{,}000}{1.348850} = 74{,}137.22.

Common errors to watch for

  • Multiplying instead of dividing by (1+i)n(1+i)^n.

Budget of Work competencies

  • gm11.t3.w1.c1
    Solve problems involving compound interest, including maturity value, future value, nominal rates, and number of terms.

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